12=0.6x^2

Solution for 12=0.6x^2 equation:

12=0.6x^2

We move all terms to the left:

12-(0.6x^2)=0

We get rid of parentheses

-0.6x^2+12=0

a = -0.6; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-0.6)·12
Δ = 28.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{28.8}}{2*-0.6}=\frac{0-\sqrt{28.8}}{-1.2}
=-\frac{\sqrt{}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{28.8}}{2*-0.6}=\frac{0+\sqrt{28.8}}{-1.2}
=\frac{\sqrt{}}{-1.2}
$